Prove: The median of a trapezoid equals half the sum of its bases.(fill in the blanks of the equation in the second picture with the correct number/letter/sign based off the first picture.)
Accepted Solution
A:
M(d/2, c/2) N=((a+b )/, c / 2) MN= (a +b)/2 - d/2) = (a+b-d)/2 AB=a CD=b-d MN=1/2 *(a+b-d) I think it should be like this