MATH SOLVE

2 months ago

Q:
# In a theater, there are 4 long rows of chairs,each with an equal number of chairs There are 5 ahort rows of chairs,each with an equal number of chairs On a crowded day, the ushers added 2 chairs to each long row and 3 chairs to each short row if x represents the number of chairs in each long row and y represents the number of chairs in each short row,the total number of chairs in the theater is given by the expression 2)Sly 3) An equivalent expression is

Accepted Solution

A:

There are 4 long rows and 5 short rows in the theater. x represents the number of chairs in each long row and y represents the number of chairs in each short row.

So, total number of chairs in 4 long rows= 4x

Total number of chairs in 5 short rows = 5y

Total number of chairs in the theater on a normal day = 4x + 5y

When 2 chairs are added to each long row, the number of chairs will change to (x+2).

So, total number of chairs in 4 long rows will be = 4(x+2)

When 3 chairs are added to each short row, the number of chairs will change to (y+3)

So, total number of chairs in 5 short rows will be = 5(y+3)

Thus, total number of chairs in the theater in rush day = 4(x+2) + 5(y+3)

= 4x + 8 + 5y + 15

= 4x + 5y + 23

Thus we can say the number of chairs increase by 23 as compared to a normal day.

So, total number of chairs in 4 long rows= 4x

Total number of chairs in 5 short rows = 5y

Total number of chairs in the theater on a normal day = 4x + 5y

When 2 chairs are added to each long row, the number of chairs will change to (x+2).

So, total number of chairs in 4 long rows will be = 4(x+2)

When 3 chairs are added to each short row, the number of chairs will change to (y+3)

So, total number of chairs in 5 short rows will be = 5(y+3)

Thus, total number of chairs in the theater in rush day = 4(x+2) + 5(y+3)

= 4x + 8 + 5y + 15

= 4x + 5y + 23

Thus we can say the number of chairs increase by 23 as compared to a normal day.