MATH SOLVE

2 months ago

Q:
# One jogger begins his run on a path at a rate of 6 miles per hour. A second jogger starts at the same point of the path as the first jogger, but jogs at a rate of 6.5 miles per hour. The second jogger begins 15 minutes after the first jogger. How long will it take the second jogger to catch up to the first jogger?

Accepted Solution

A:

Answer:The answer to your question is: three hours.Step-by-step explanation:dataJogger 1 = 6 mi/hJogger 2 = 6.5 miles/h , starts 15 min (0.25 h) after the first JoggerTime when the second jogger catch the first jogger = ?ProcessAdvantage of the first jogger d = vt = 6(0.25) = 1.5 miDistance where they meet 1.5 + 6t = 6.5tFind the t value 6.5t - 6t = 1.5 0.5 t = 1.5 t = 1.5 / 0.5 t = 3 hours